Answer to 7.11 Version 0 |
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👤 Author: by fmissy 2017-01-08 11:41:38 |
a.The content of matrix Need is P0(0 0 0 0) P1(0 7 5 0) P2(1 0 0 2) P3(0 0 2 0) P4(0 6 4 0)
b.The system is in a safe state. Because the matrix of Available is (1 5 2 0), P0 and P3 both can run. When P3 is finished, it can release its resource, so other process is allowed to run.