homework9_沈宇帆_2018329621232 Version 0 |
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👤 Author: by 512858048qqcom 2020-12-08 06:48:24 |
Logical address is divided into two parts:
1. Page number: N bits
2. Page offset: 2^N bits
Physical address = page base addr + page offset
If we have the follow page table:
page number block number
0 1
1 3
2 5
3 7
And the Page size is 1kb, the 13 bits logical address is 010 0 000 010 100(p=2,d=20)
Answer:
Because we can get page 2 maps to 5,so the physical address is
5*(1kb) + 20 = 1 010 000 010 100