| 2019329621127 毛雷溥浩 homework4 Version 0 |
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| 👤 Author: by 2972850556qqcom 2021-09-27 12:13:18
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Process Arrive Time Burst Time
p1 0 8
p2 0 6
p3 3 4
p4 5 10
p5 10 1
consider Preemptive SJF,the shortest average time is?
p2 p3 p5 p1 p4
0 6 10 11 19 29
p1=11
p2=0
p3=6
p4=19
p5=10
average time=7.4
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