2019329621182-刘辰萱-homework-8 Version 0 |
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👤 Author: by rootfreanjacn 2021-12-25 22:07:11 |
代码:
//
// main.cpp
// Banker's algorithm
//
// Created by FreanJa L on 2021/12/26.
//
#include <stdio.h>
int main()
{
//P0, P1, P2, P3, P4 are the Process names here
int i, j, k;
const int n = 5; //Number of processes
const int m = 3; //Number of resources
int alloc[5][3] = { { 0, 1, 0 }, //P0 //Allocation Matrix
{ 2, 0, 0 }, //P1
{ 3, 0, 2 }, //P2
{ 2, 1, 1 }, //P3
{ 0, 0, 2 } }; //P4
int max[5][3] = { { 7, 5, 3 }, //P0 //MAX Matrix
{ 3, 2, 2 }, //P1
{ 9, 0, 2 }, //P2
{ 2, 2, 2 }, //P3
{ 4, 3, 3 } }; //P4
int avail[3] = { 3, 3, 2 }; //Available Resources
int f[n], ans[n], ind = 0;
for (k = 0; k < n; k++) {
f[k] = 0;
}
int need[n][m];
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++)
need[i][j] = max[i][j] - alloc[i][j];
}
int y = 0;
for (k = 0; k < 5; k++) {
for (i = 0; i < n; i++) {
if (f[i] == 0) {
int flag = 0;
for (j = 0; j < m; j++) {
if (need[i][j] > avail[j]) {
flag = 1;
break;
}
}
if (flag == 0) {
ans[ind++] = i;
for (y = 0; y < m; y++)
avail[y] += alloc[i][y];
f[i] = 1;
}
}
}
}
printf("Following is the SAFE Sequence\n");
for (i = 0; i < n - 1; i++)
printf(" P%d ->", ans[i]);
printf(" P%d\n", ans[n - 1]);
return (0);
}
运行结果:
Following is the SAFE Sequence
P1 -> P3 -> P4 -> P0 -> P2
Program ended with exit code: 0