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2019329621249陈雅冰homework4 Version 0
👤 Author: by 1422679707qqcom 2021-12-25 17:14:43

Processes Burst time Arrive time
P0 10 2
P1 8 3
P2 2 8
P3 6 6
FCFS:
PO = 0; P1 = 9; P2 = 18; P3 = 14
Average time = ( 0 +9+18+14 ) /4 = 10.25
RR:
PO = 16;P1 = 2; P2 = 0; P3 = 7
Average time = (16+2 ＋0 + 7)/ 4 = 6.25

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