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Homework 6 K BABANAZAR 2019529628030 Version 0
👤 Author: by wx287_oz26ft-3_gi3ergmjooq4q7gvhl0 2022-02-17 13:12:16
Solution:

Problem: Whenever a process is constantly checking value while waiting (see while(s==0)) and wasting CPU cycles, we can take the following train of thought to avoid this situation:

P(Semaphore s)

{

s=s-1;

if(s<0){

block();

}

}

V(Semaphore s)

{

s=s+1;

if(s >=0){

wakeup(p);

}

}

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