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> 2019529628010 T.J.BONOLO

Homework 4 Version 0
👤 Author: by jtjabakagmailcom 2022-01-07 16:37:29

Processes Burst time Arrive time

P0 10 2

P1 8 3

P2 2 8

P3 6 6

FCFS:

P0=0; P1=9; P2=18; P3=14

Average time= (0+9+18+14)/4=10.25

RR;

P0=16; P1=2; P2=0; P3=7

AVG time= (16+2+0+7)/4=6.25

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